AE 14: Integration

Suggested answers

Application exercise
Answers

In this exercise, we will:

Common functions + their Integrals

  1. Power Function:
  • Function:

f(x)=xn

  • Integral:

xndx=xn+1n+1+C(n1)

  1. Exponential Function:
  • Function:

f(x)=ex

  • Integral:

exdx=ex+C

  • Function:

f(x)=ax

  • Integral:

axdx=axln(a)+C

  1. Natural Logarithm
  • Function:

f(x)=ln(x)

  • Integral:

ln(x)dx=xln(x)x+C

  1. Trigonometric Functions
  • Function:

f(x)=sin(x)

  • Integral:

sin(x)dx=cos(x)+C

  • Function:

f(x)=cos(x)

  • Integral:

cos(x)dx=sin(x)+C

  • Function:

f(x)=tan(x)

  • Integral:

tan(x)dx=ln|cos(x)|+C=ln|sec(x)|+C

  1. Hyperbolic Functions
  • Function:

f(x)=sinh(x)

  • Integral:

sinh(x)dx=cosh(x)+C

  • Function:

f(x)=cosh(x)

  • Integral:

cosh(x)dx=sinh(x)+C

Integrals

For each problem, find the integral of the given function. Show all steps clearly.

Exercise 1

Function:

f(x)=5x3

Solution:

  • The power rule for integration states that xn dx=xn+1n+1+C

  • Applying the power rule:

5x3dx=5x3+13+1+C=5x44+C

Exercise 2

Function:

g(x)=x

Solution:

  • Rewrite the function with a fractional exponent: x=x1/2.

  • Apply the power rule:

g(x)=x1/2

x1/2dx=x1/2dx=x1/2+11/2+1+C=x3/23/2+C=23x3/2+C

Exercise 3

Function:

h(x)=ln(x)

Solution:

  • Use the integral of the natural logarithm function:

ln(x)dx=xln(x)x+C

Intermediate Derivatives Using Chain Rule and Product Rule

Exercise 4

Function:

xex dx

Solution

  • Identify the parts: Let u=x and dv=ex dx

  • Differentiate and integrate:

    • Differentiate: du=dx

    • Integrate: v=ex

  • Apply the integration by parts formula: u dv=uvv du

xexdx=xexexdx

  • Simplify the integral:

xexdx=xexex+C

  • Final answer:

xexdx=ex(x1)+C

Exercise 5

Function:

xln(x) dx

Solution:

  • Identify the parts: u=ln(x) and dv=x dx

  • Differentiate and integrate:

    • Differentiate: du=1x dx

    • Integrate: v=x22

  • Apply the integration by parts formula: u dv=uvv du

  • Substitute the parts:

x ln(x) dx=ln(x)x22x221x dx

  • Simplify the integral:

xln(x) dx=x2ln(x)212x dx

  • Integrate the remaining part:

12x dx=12x22=x24

  • Combine the results:

xln(x) dx=x2ln(x)2x24+C

  • Final answer:

xln(x) dx=x22ln(x)x24+C

Advanced Integral

Exercise 6

Function:

xsin(x2) dx

Solution:

  • Identify the substitution: Let u=x2

  • Differentiate and solve for du:

    • du=2x dx

    • 12du=x dx

  • Substitute into the integral

xsin(x2) dx=sin(u)12 du

  • Integrate:

12sin(u) du=12(cos(u))+C

  • Substitute back into the original variable:

12(cos(u))+C=12cos(x2)+C

  • Final answer

xsin(x2) dx=12cos(x2)+C